`count = 0
arr = list(map(int, input().split()))
n = arr[0]
l = []
height = arr[1:]
height.sort()
z = []
if n <= 2:
print(2)
exit()
for i in range(n):
for h in range(i+1, n):
z.append(height[h]-height[i])
for m in set(z):
l.append(z.count(m))
print(max(l))`
The TLE has been removed. But you have to evaluate why this algorithm gives wrong answer.
for m in set(z):
The time complexity of this step should be close to n^2.
Then complexity of count is n.
Complexity of program O(n^3)
count = 0
arr = list(map(int, input().split()))
n = arr[0]
l = []
height = arr[1:]
height.sort()
z = []
if n <= 2:
print(2)
exit()
for i in range(n):
for h in range(i+1, n):
z.append(height[h]-height[i])
mp = {}
for m in z:
if m not in mp:
mp[m] = 0
mp[m] += 1
print(max(mp.values()))