# PROBLEM LINK:

Practice

Contest: Division 1

Contest: Division 2

Contest: Division 3

Contest: Division 4

* Author:* utkarsh_25dec

*iceknight1093, tabr*

**Testers:***iceknight1093*

**Editorialist:**# DIFFICULTY:

TBD

# PREREQUISITES:

None

# PROBLEM:

Given three integers A, B, C; determine if the product of some two of them is negative.

# EXPLANATION:

There are only three possible products: A\times B, A\times C, B\times C.

Compute all three of them and check if any of them is negative.

Alternatively, note that a negative product requires one positive and one negative number, so check if at least one of each exists.

# TIME COMPLEXITY:

\mathcal{O}(1) per testcase.

# CODE:

## Code (Python)

```
for _ in range(int(input())):
a, b, c = map(int, input().split())
print('Yes' if min(a, b, c) < 0 and max(a, b, c) > 0 else 'No')
```