how to find total number of factor of any number less than a given number ?
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Please look up the forum before asking questions straightaway.
i am not asking number of factors of a number , the question is total number of a factors less than a given number x for each query…
ex: let, n = 36 and x=12 where 1<=n <=1000000 and 1<=x<=10000
so , 36 = 1,2,3,4,6,9,12,18,36.
so answer is 5 …
I read your query and I am here with my solution. I hope it helps
n = int(input("Enter large number: "))
x = int(input("Enter your limit: "))
factors = []
for i in range(2,n):
if n%i == 0 and i<x:
factors.append(i)
print(factors, f"Number of factors = {len(factors)}")
it will give tle
wdym?
Was that all you needed or is there something else?
your approach is right but constraint is large so it will give tle
What is tle?
TIME LIMIT EXCEED
Just link to the Problem rather than making us guess what you want.
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this is from the ongoing long challenge…
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