NUMPATH - Editorial

#1

Author: Vineet Paliwal
Tester: Roman Rubanenko
Editorialist: Jingbo Shang

Medium

PREREQUISITES:

Dynamic Programming, Suffix Sum, Fenwick Tree

PROBLEM:

Given a Directed-Acyclic-Graph (DAG) G = (V, E) in which node i has edges to nodes in [i + 1, i + N*], find how many paths are there between S* and T.

EXPLANATION:

This DAG is really special and the order of 1 … V is exactly same as its topo order in which edges are only existed from previous nodes to their later ones.

Use F* to state the number of different paths starting from node i to node T.

    Initially F[T] = 1, F[others] = 0.


The transmission can be described as following:

    For i = T - 1 downto 1
F* = \sum_{v = i + 1} ^ {i + N*}


To speed up this transmission procedure, we can use a Fenwick Tree to get the sum. But we can achieve it in a simpler way as following, using suffix sum.

    suffixSum[] = 0;
suffixSum[T] = 1;
For i = T - 1 downto 1
F* = G[i + N*];
G* = G[i + 1] + F*


To answer each query, just directly output the F[S*]. Therefore, the time complexity is O(N + Q) in total.

AUTHOR’S AND TESTER’S SOLUTIONS:

Author’s solution can be found here.
Tester’s solution can be found here.

#2

http://www.codechef.com/viewsolution/7049475

Can anyone suggest how to reduce time? I am exceeding the time limit. I am working with C.