# PROBLEM LINK:

* Author:* Setter’s name

*Tester’s name*

**Tester:***Editorialist’s name*

**Editorialist:**# DIFFICULTY:

cakewalk .

# PROBLEM:

Given **T** test case. For each test case, you are given a String **S** so you need to convert that given String into secure String by Encryption. There is a way to encrypt the message by shifting the alphabets by 3 alphabets in a circular manner of String **S**. Where **S** contains capital alphabets.

# EXPLANATION:

So after reading this problem, some people will think that what if we just add 3 into ASCII value so what will be the character for **x,y,z** let me clear that its mention above that you can shift the alphabets by 3 in **Circular** manner.

There is a simple approach used by me that we can get ASCII of each character. Hence it contains a capital letter we subtract 65. So the character is between(0-25). Suppose the character is x so calculate **x=(x+3) % 26** is a new character we need to place, hence it is between 0-25 we add 65 to get a character in the upper letter. And there is one important condition don't forget to skip ' ' (space) character.

# SOLUTIONS:

## Setter's Solution

import java.io.*; class NXS { public static void main (String[] args)throws IOException { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); int test = Integer.parseInt(br.readLine()); while(test-->0){ String s= br.readLine(); int n=s.length(); String ans=""; for(int i =0 ; i<n ;i++){ if(s.charAt(i)==' '){ ans+=' '; continue; } int x = s.charAt(i)-65; x=(x+3)%26; ans+=(char)(x+65); } System.out.println(ans); } } }

Feel free to Share your approach, if you want to. (even if its same) . Suggestions are welcomed as always had been.