# PASSORFAIL - Editorial

Setter: Utkasrsh Gupta
Tester: Manan Grover
Editorialist: Ajit Sharma Kasturi

CAKEWALK

None

## PROBLEM:

Chef writes and exam consisting of N questions. Chef gets 3 marks for every correct answer and -1 marks for every incorrect answer.The passing marks is P for this course. Chef has answered X questions correct and the remaining questions incorrect. We need to find whether chef will pass the exam or not.

## EXPLANATION:

• Number of questions answered correctly is X. Therefore, number of questions answered incorrectly is N-X.

• The number of marks the chef will get will then be 3\cdot X - (N-X).

• Since the passing marks is P, chef needs atleast P marks to pass.

• Therefore, if 3\cdot X - (N-X) \geq P we ouput PASS, else we output FAIL.

## TIME COMPLEXITY:

O(1) for each testcase.

## SOLUTION:

Editorialist's solution
#include <bits/stdc++.h>
using namespace std;

int main()
{
int tests;
cin >> tests;
while (tests--)
{
int n, x, p;
cin >> n >> x >> p;

if (3 * x - (n - x) >= p)
cout << "PASS" << endl;
else
cout << "FAIL" << endl;
}
}


Setter's solution
//Utkarsh.25dec
#include <bits/stdc++.h>
#include <chrono>
#include <random>
#define ll long long int
#define ull unsigned long long int
#define pb push_back
#define mp make_pair
#define mod 1000000007
#define rep(i,n) for(ll i=0;i<n;i++)
#define loop(i,a,b) for(ll i=a;i<=b;i++)
#define vi vector <int>
#define vs vector <string>
#define vc vector <char>
#define vl vector <ll>
#define all(c) (c).begin(),(c).end()
#define max3(a,b,c) max(max(a,b),c)
#define min3(a,b,c) min(min(a,b),c)
#define deb(x) cerr<<#x<<' '<<'='<<' '<<x<<'\n'
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
// ordered_set s ; s.order_of_key(val)  no. of elements strictly less than val
// s.find_by_order(i)  itertor to ith element (0 indexed)
typedef vector<vector<ll>> matrix;
ll power(ll a,ll b) {ll res=1;a%=mod; assert(b>=0); for(;b;b>>=1){if(b&1)res=res*a%mod;a=a*a%mod;}return res;}
ll modInverse(ll a){return power(a,mod-2);}
const int N=500023;
bool vis[N];
void solve()
{
ll n,x,p;
cin>>n>>x>>p;
assert(n>=1 && n<=100);
assert(x>=0 && x<=n);
assert(p>=0 && p<=3*n);
ll marks=3*x-(n-x);
if(marks>=p)
cout<<"PASS\n";
else
cout<<"FAIL\n";
}
int main()
{
#ifndef ONLINE_JUDGE
freopen("input.txt", "r", stdin);
freopen("output.txt", "w", stdout);
#endif
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int T=1;
cin>>T;
assert(T>=1 && T<=1000);
int t=0;
while(t++<T)
{
//cout<<"Case #"<<t<<":"<<' ';
solve();
//cout<<'\n';
}
cerr << "Time : " << 1000 * ((double)clock()) / (double)CLOCKS_PER_SEC << "ms\n";
}


Tester's solution
#include <bits/stdc++.h>
using namespace std;
int main(){
ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
int t;
cin>>t;
while(t--){
int n,x,p;
cin>>n>>x>>p;
if(p <= 4 * x - n){
cout<<"PASS\n";
}else{
cout<<"FAIL\n";
}
}
return 0;
}



Please comment below if you have any questions, alternate solutions, or suggestions.

hii can you help me i am new in code chef and i am trying to do questions and i know basics but i can’t solve the problems can you help me to figure out.

Hey @riteshsharma7, don’t worry, every competitive programmer has been in the same phase at some point of their journey.

For starters, I would suggest you to avoid harder problems and practice problems that are just a little above your current skill level. This will help you avoid burnout from competitive programming and help you practice consistently, which is the most important factor as per my experience.

But at the same time you also need to make sure that you are not solving only very easy problems, as it will create a plateau. You would feel that you are working hard but still not improving.
I would recommend using the codechef’s rating system in order to classify problems according to their difficulty.