Problem Name: Factorial, Says wrong answer can anyone tell me whats wrong?

Problem Factorial - link to problem
Here is my solution:-

#include<stdio.h>
#include <stdlib.h>
int main()

{

 int noofinputs; 

 int i;

int div= 5;

    int zero = 0;

    scanf("%d",&noofinputs);
    
    int *no = malloc(noofinputs*sizeof(int));

    for(i=0;i<noofinputs;i++)
    {
      scanf("%d",&no[i]);
    }
    
    for(i=0;i<noofinputs;i++)
    {
        if(no[i]==5)
        {
            printf("1\n");
        }
        else if(no[i]<5)
        {
            printf("0\n");
        }   
        else
        {
            while(div<no[i])
            {
                zero = zero + (no[i]/div);
                div = 5*div;
            }
            printf("%d\n",zero);
            div = 5;
            zero = 0;
        } 
    }       
    return 0;
}

1)The condition in the loop should be : while(div<=no[i]). i.e less than or equal to.

2)no need to take all inputs in array. take input and output the answer and then proceed to next case.

I guess that should work. Here is accepted code using array and also another version of your code without using array .

1 Like

Hello,
Even If you change the condition while(div<=no[i]), it won’t give the correct output.
I have modified your code as below…

#include<stdio.h>
#include <stdlib.h>
int main()
 
{
 
 int noofinputs;
 
 int i;
 
int div= 120;
 
    int zero = 0;
 
    scanf("%d",&noofinputs);
 
    int *no = malloc(noofinputs*sizeof(int));
 
    for(i=0;i<noofinputs;i++)
    {
      scanf("%d",&no[i]);
    }
 
    for(i=0;i<noofinputs;i++)
    {
        if(no[i]==5)
        {
            printf("1\n");
        }
        else if(no[i]<5)
        {
            printf("0\n");
        }   
        else
        {
            while(no[i]>5)
            {
                //zero = zero + (no[i]/div);
                div = div*no[i];
                no[i]--;
            }
            printf("%d\n",div);
            div = 120;
           // zero = 0;
        } 
    }       
    getch();
    return 0;
} 

It is compiling and returning the required answer… Thank you…

He is reseting div and zero in loop and int is big enough for numbers up to 10^9.

1 Like

@betlista didnt notice. my bad!!

@kcahdog , @betlista im sure we can do it without storing in an array as u said, but i wanna know why is my code wrong? Like whats the mistake in this code?

And why you skipped 1.) ? Your code for input

1
25

returns 5, but 25! is 15511210043330985984000000

oh Yes it should be <= , thankyou @betlista any thing else u feel is wrong?

just try to submit it :wink: It seems fine to me. Maybe those test if(no[i]==5), if(no[i]<5) are useless but it’s not a problem :wink:

They finally accepted it. :stuck_out_tongue:

Congrats, but I didn’t find the bug, @kcahdog did :wink: You should up vote and/or accept his answer :wink:

@tb90 your code got accepted only by changing the condition to “<=”. that was the only mistake in your code.

@amanachiever Here is the code where “<” is changed to “<=”. it got accepted!! :- CodeChef: Practical coding for everyone

Changing

while(div<no[i])
{
    zero = zero + (no[i]/div);
    div = 5*div;
}

to

while(no[i]>5)
{
    div = div*no[i];
    no[i]--;
}

is not the same as changing < to <= or you think so?