QLK05 - EDITORIAL

PROBLEM LINK:

Practice

Contest

Author: Pritish Priyatosh Nayak

Tester: Saytabrat Panda

Editorialist: Pritish Priyatosh Nayak

DIFFICULTY:

Cakewalk

PREREQUISITES:

None

PROBLEM:

The problem is basically :
Given N and K, check if N^N \geq K.

QUICK EXPLANATION:

To avoid overflow while calculating we can print “Yes” for all cases where N \geq 16 otherwise calculate N^N manually and check the condition.

EXPLANATION:

From the constraints its clear that we need either O(1) solution or O(logN) solution.

But we cannot calculate N^N for any N \geq 16 because 16^{16} turns out to be 2^{64} and even the maximum positive number which can be stored in unsigned long long data type of C/C++ is 2^64-1.
If we actually try to calculate N^N we will run into overflow error.
Even with languages like Python it’s still not possible to calculate N^N for such large N because it will be very slow.

But K is at max 10^{18} which is less than 16^{16} , so we need to only check for N less than 16 manually and compare it with K.
If N is greater than or equal to 16, the answer is obviously “Yes”.

Alternate approach:
You could have used the fact that if N^N \geq K then Nlog(N) \geq log(K).
Using the inbuilt log functions , it could have been solved easily without having to use any short-cut tricks.

SOLUTIONS:

Setter's/Editorialist's Solution
#include<bits/stdc++.h>
using namespace std;
long long pow(long long x,long long y)
{
	long long res=1;
	for(long long i=1;i<=y;i++)
		res*=x;
	return res;
}
int main()
{
	int t;
	cin>>t;
	while(t--)
	{
		long long n,k;
		cin>>n>>k;
		if(n>=16)
			cout<<"Yes\n";
		else if(pow(n,n)>=k)
			cout<<"Yes\n";
		else cout<<"No\n";
	}
	return 0;
}
Tester's Solution
import java.util.*;import java.io.*;import java.math.*;
 
public class Main
{
 
    public static void process()throws IOException
    {
        long n=nl(),k=nl();

        assert (n>1e18 || k>1e18):"N or K > 1e18";
        pn((n*Math.log(n)>=Math.log(k))?"Yes":"No");
    }
 
 
    static AnotherReader sc;
    static PrintWriter out;
    public static void main(String[]args)throws IOException
    {
        out = new PrintWriter(System.out);
        sc=new AnotherReader();
        boolean oj = true;
 
        //oj = System.getProperty("ONLINE_JUDGE") != null;
        if(!oj) sc=new AnotherReader(100);
 
        long s = System.currentTimeMillis();
        int t=1;
        t=ni();
        while(t-->0)
            process();
        out.flush();
        if(!oj)
            System.out.println(System.currentTimeMillis()-s+"ms");
        System.out.close();  
    }
    
    
    static void pn(Object o){out.println(o);}
    static void p(Object o){out.print(o);}
    static void pni(Object o){out.println(o);System.out.flush();}
    static int ni()throws IOException{return sc.nextInt();}
    static long nl()throws IOException{return sc.nextLong();}
    static double nd()throws IOException{return sc.nextDouble();}
    static String nln()throws IOException{return sc.nextLine();}
    static long gcd(long a, long b)throws IOException{return (b==0)?a:gcd(b,a%b);}
    static int gcd(int a, int b)throws IOException{return (b==0)?a:gcd(b,a%b);}
    static int bit(long n)throws IOException{return (n==0)?0:(1+bit(n&(n-1)));}
    static boolean multipleTC=false;
    static long mod=(long)1e9+7l;
 
    static void r_sort(int arr[],int n){
        Random r = new Random(); 
        for (int i = n-1; i > 0; i--){ 
            int j = r.nextInt(i+1); 
                  
            int temp = arr[i]; 
            arr[i] = arr[j]; 
            arr[j] = temp; 
        } 
        Arrays.sort(arr); 
    }
 
    static long mpow(long x, long n) {
        if(n == 0)
            return 1;
        if(n % 2 == 0) {
            long root = mpow(x, n / 2);
            return root * root % mod;
        }else {
            return x * mpow(x, n - 1) % mod;
        }
    }
    
    static long mcomb(long a, long b) {
        if(b > a - b)
            return mcomb(a, a - b);
        long m = 1;
        long d = 1;
        long i;
        for(i = 0; i < b; i++) {
            m *= (a - i);
            m %= mod;
            d *= (i + 1);
            d %= mod;
        }
        long ans = m * mpow(d, mod - 2) % mod;
        return ans;
    }
/////////////////////////////////////////////////////////////////////////////////////////////////////////
 
    static class AnotherReader{BufferedReader br; StringTokenizer st;
    AnotherReader()throws FileNotFoundException{
    br=new BufferedReader(new InputStreamReader(System.in));}
    AnotherReader(int a)throws FileNotFoundException{
    br = new BufferedReader(new FileReader("input.txt"));}
    String next()throws IOException{
    while (st == null || !st.hasMoreElements()) {try{
    st = new StringTokenizer(br.readLine());}
    catch (IOException  e){ e.printStackTrace(); }}
    return st.nextToken(); } int nextInt() throws IOException{
    return Integer.parseInt(next());}
    long nextLong() throws IOException
    {return Long.parseLong(next());}
    double nextDouble()throws IOException { return Double.parseDouble(next()); }
    String nextLine() throws IOException{ String str = ""; try{
    str = br.readLine();} catch (IOException e){
    e.printStackTrace();} return str;}}
/////////////////////////////////////////////////////////////////////////////////////////////////////////////
} 

2 Likes

nice question bro,but as usual i m damn stupid :rofl::rofl: