 # QUALIFY - Editorial

Setter: Utkarsh Gupta
Tester: Abhinav Sharma, Manan Grover
Editorialist: Lavish Gupta

Cakewalk

None

# PROBLEM:

In a coding contest, there are two types of problems:

• Easy problems, which are worth 1 point each
• Hard problems, which are worth 2 points each

To qualify for the next round, a contestant must score at least X points. Chef solved A Easy problems and B Hard problems. Will Chef qualify or not?

# EXPLANATION:

Chef has solved A Easy problems and B Hard problems, so total number of points that the Chef has got = A + 2\cdot B.

If A + 2 \cdot B \geq X, then Chef has qualified, otherwise Chef has not qualified.

# TIME COMPLEXITY:

O(1) for each test case.

# SOLUTION:

Editorialist's Solution
#include<bits/stdc++.h>
#define ll long long
#define pll pair<ll ,ll>
using namespace std ;
const ll z = 998244353 ;

int main()
{

int t ;
cin >> t ;
while(t--)
{
int x , a , b ;
cin >> x >> a >> b ;

int points = a + 2*b ;

if(points >= x)
cout << "QUALIFY" << endl ;
else
cout << "NOTQUALIFY" << endl ;
}

return 0;
}