#include
using namespace std;
int main() {
int t;
cin>>t;
while(t--){
int num1,num2;
cin>>num1>>num2;
int a= max(num1,num2),b=min(num1,num2),r=a%b;
while(r!=0){
a=b;
b=r;
r=a%b;
}
cout<<b<<" "<<((num1*num2)/b)<<endl;
}
return 0;
}
termii
#2
link to problem: Contest Page | CodeChef
Input: A (=num1), B (=num2) ≤ 10⁶
the error: cout<<b<<" "<<((num1*num2)/b)<<endl;
num1 * num2 ≤ 10¹²
if both num1 and num2 are ints, you may cause an integer-overflow. Therefore you should use long long for at least one of them.
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yeah i see,thank you very much for the help^_^
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