# PROBLEM LINK:

Practice

Contest: Division 1

Contest: Division 2

Contest: Division 3

Contest: Division 4

* Author:* notsoloud

*iceknight1093, yash_daga*

**Testers:***iceknight1093*

**Editorialist:**# DIFFICULTY:

TBD

# PREREQUISITES:

None

# PROBLEM:

Given the times taken by Alice, Bob, and Charlie to run a 400\ M race, (A, B, C respectively), who had the highest average speed?

# EXPLANATION:

Using the formula \text{distance} = \text{speed} \times \text{time}, we can see that the highest average speed corresponds to the lowest time taken.

So, find who out of Alice/Bob/Charlie took the lowest time; that person also has the highest average speed.

This can be implemented with a couple of `if`

conditions.

# TIME COMPLEXITY:

\mathcal{O}(1) per testcase.

# CODE:

## Editorialist's code (Python)

```
for _ in range(int(input())):
x, y, z = map(int, input().split())
if x == min(x, y, z): print('Alice')
if y == min(x, y, z): print('Bob')
if z == min(x, y, z): print('Charlie')
```