# PROBLEM LINK: Contest Practice

**Author:** Baban Gain

**Editorialist:** Baban Gain

# DIFFICULTY:

EASY

# PREREQUISITES:

Area, Square, Rectangle

# PROBLEM:

Given two sides of rectangle, A and B you need to calculate sum of area of squares can be formed within it.

# EXPLANATION:

No. of squares of side i in a A x B is given by max(0, (A-i+1) * (B-i+1)).

As side of a square cannot be less than or equals 0

We will start from side = 1, Area per square = 1 * 1 = 1, No. of squares = A * B

side = 2, Area per square = 2 * 2 = 4, No. of squares = (A-1) * (B-1)

side = 3, Area per square = 3 * 3 = 9, No. of squares = (A-2) * (B-2)

and so on till No. of squares > 0.

So, multiply area per square with No. of squares and add them. Then print the result

# AUTHORâ€™S SOLUTION:

Authorâ€™s solution can be found here.