https://www.codechef.com/viewsolution/26077830
can anyone tell me what is wrong with this solution ?
Here’s a few failing testcases:
1
10000 10000 9000 9000
1
10000 10000 10000 10000
1
2 6 3 4
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Here’s a solution. The logic is that there should be a pair of pairs of sides that bear equal values each.
ok the last case
1
2 6 3 4
proves this approach is wrong
i was also thinking about such pair where there is chance of being perfect square not being equal ,thanks for the help
gotcha
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