Roots of equation

editorial
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1

Practice

Author: Aryan KD
Tester: Aryan KD
Editorialist: Aryan KD

DIFFICULTY:

CAKEWALK, SIMPLE, EASY.

PREREQUISITES:

Math .

PROBLEM:

You have given a quadratic equation you have to find a nature of root in it. you have given three coefficient A,B,C of a quadratic equation AX^2+BX+C . nature of root is depend on the value of discriminant which is equal to (B^2-4 x A x C) where A is first term B is 2nd term and C is 3rd term of equation

there is 3 type of root can be possible

  • 1 imaginary : if the value of discriminant less than 0 .
  • 2 real : if the value of discriminant greater than 0 .
  • 3 equal : if the value of discriminant is equal to 0 .

EXPLANATION:

We have just given three numbers that is A , B and C we have to find value of discriminant and we have to compare it from 0 if the given values is equal to 0 then we have to print equal
if the value of discriminant less than 0 then print imaginary and if the value of discriminant greater than 0 print real
value of discriminant is found by given formula B^2 - 4AC
for example :innocent: 3 8 4
here A=3 B=8 C=4
value of discriminant is B^2-4xAxC = 8^2-4x3x4 = 16 that is greater than 0 there for output is real

SOLUTIONS:

Setter's Solution

#include<bits/stdc++.h>
using namespace std;
void testcase()
{
int a,b,c;
cin>>a>>b>>c;
int d= (bb)-(4a*c);
if(d<0){
cout<<“imaginary”;
}
else if(d==0){
cout<<“equal”;
}
else{
cout<<“real”;
}
}
int main()
{
int t;
cin>>t;
while(t–)
{
testcase();
cout<<endl;
}
return 0;
}

Tester's Solution

#include<bits/stdc++.h>
using namespace std;
void testcase()
{
int a,b,c;
cin>>a>>b>>c;
int d= (bb)-(4a*c);
if(d<0){
cout<<“imaginary”;
}
else if(d==0){
cout<<“equal”;
}
else{
cout<<“real”;
}
}
int main()
{
int t;
cin>>t;
while(t–)
{
testcase();
cout<<endl;
}
return 0;
}

Editorialist's Solution

#include<bits/stdc++.h>
using namespace std;
void testcase()
{
int a,b,c;
cin>>a>>b>>c;
int d= (bb)-(4a*c);
if(d<0){
cout<<“imaginary”;
}
else if(d==0){
cout<<“equal”;
}
else{
cout<<“real”;
}
}
int main()
{
int t;
cin>>t;
while(t–)
{
testcase();
cout<<endl;
}
return 0;
}