Run time error in LPC problem

feedback
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1

Problem Link: LPC Problem - CodeChef

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Can anyone please explain what’s the problem with my code, it is correct for one test case but shows runtime error for other.

code-
include <bits/stdc++.h>
using namespace std;

int main() {
int t;
cin>>t;
while(t–){
int n,m;
cin>>n>>m;
string s;
string k;
cin>>s;
cin>>k;
int mini=INT_MAX;
int res=0;
string str,final;
for(int i=0;i<=(n-m);i++)
{
str=s.substr(i,m);
int stri=stoi(str);
int key=stoi(k);
if(abs(stri-key)<mini){
mini=abs(stri-key);
final=str;
}

}

for(int i=0;i<m;i++)
{
    int diff = abs((k[i] - '0') - (final[i] - '0'));
    if(diff>5)
    {
        diff=10-diff;
    }
    res+=diff;
}
cout<<res<<endl;

}
return 0;
}

2

@rajchaurasiya
U are getting runtime error because of this line.
for(int i=0;i<=(n-m);i++)
the = is making problem of run time error and making it out of bound.

3

Well, there are some logical issues looking with your code, you can try below code to fix this error.

#include <bits/stdc++.h>
using namespace std;

int main() {
    int t;
    cin >> t;
    while (t--) {
        int n, m;
        cin >> n >> m;
        string s;
        string k;
        cin >> s;
        cin >> k;
        int mini = INT_MAX;
        int res = 0;
        string final;
        for (int i = 0; i <= (n - m); i++) {
            string str = s.substr(i, m);
            int stri = stoi(str);
            int key = stoi(k);
            if (abs(stri - key) < mini) {
                mini = abs(stri - key);
                final = str;
            }
        }

        for (int i = 0; i < m; i++) {
            int diff = abs((k[i] - '0') - (final[i] - '0'));
            if (diff > 5) {
                diff = 10 - diff;
            }
            res += diff;
        }
        cout << res << endl;
    }
    return 0;
}

Thanks