Runtime(SIGABRT) error on the problem CLFIBD

This is my first problem in CodeChef. I am getting Runtime(SIGBART) error on the following code. I tested the input cases given in the question and got the same output. But, still I am getting an error. Can anyone explain why I am getting the error and how can I rectify it ?
Here is my solution

There are multiple reasons behind your code failing!

#include <iostream>
#include <vector>
#include <bits/stdc++.h>

using namespace std;

void show(vector<int> v) {
    for (int num:v)
        cout << num << " ";

int main() {
    string alphabets = "abcdefghijklmnopqrstuvwxyz";
    int t;
    cin >> t;
    vector<string> test_strings;
    for (int i = 0; i < t; i++) {
        string tes;
        cin >> tes;
    for (int i = 0; i < t; i++) {
        string test =;
        vector<int> counts;
        for (char c:alphabets) {
            int c_count = count(test.begin(), test.end(), c);
            if (c_count > 0)
        sort(counts.begin(), counts.end());
        for (int i = 0; i < counts.size() - 2; i++)
            if ( + 2) == + + 1)) {
                if (i == counts.size() - 3)
                    cout << "Dynamic\n";
            } else
                cout << "Not\n";


    return 0;

Note that the constraints state that the length of the input string is greater than 1.

For this input: 1 a

Your code at this line: + 2) == + + 1) would throw an out of range exception.

(terminate called after throwing an instance of 'std::out_of_range'
  what():  vector::_M_range_check: __n (which is 2) >= this->size() (which is 1))

Also, you the local variable ‘i’ declared in the nested for loop hides the previous declaration of i in the outer for loop.

If a string is of length 1 or 2, can we call it ‘Dynamic’ ?

Well, it’s mentioned:

Note that if the number of distinct characters in the string is less than 3, i.e. if |C|<3, then the string is always dynamic.

So according to me, your code is valid for |C| > 3 else just print dynamic!

Accept the answer if it helped!