Can any one tell what’s wrong in code which is very short and simple.

passing test case but overall wrong answer.

problem link:-link text

my solution:- link text

I cant believe it getting wrong for 3 times for such a basic level problem. Plz I want to know what part in code is producing wrong answer.

thanks

check for this test case, ur answer is “Draw” but actual answer will be Kefa

```
1
0 10 6 4 3
```

edit:-- **line no 41 u r making error**

```
if(cc==ck)
printf("Draw\n");
```

**EDIT:- ** Bro after seeing ur below answer, yes ur logic seems to be almost correct but a small mistake…

check ur else part when counter1

```
else // both take same steps
{
if (vel1 greater than vel2)
person1 reaches first
else
person2 reaches first
}
```

ok so in above given **example 0 10 6 4 3**

*i am assuming counter in seconds*

**counter1 will be 1sec (6/4) and remainder is 2 more distance to cover as (6-0)%4**

counter2 will be 1sec (4/3) and remainder is 1 (1 more distance to cover) as (10-6)%3

**So according to else part

counter1==counter2 //true No issue here

then chef have to cover remaining distance of 2 meter where his speed is 4 meter/sec so it will take extra 2/4= **.5 sec**

and kefa have to cover remaining distance of 1 meter where his speed is 3 meter/sec** which will take nearly 1/3 = **.33 sec**

so kefa will reach early

**so Kefa should be actual answer…**

but according to ur logic, whose velocity is higher will reach first…

velocity of chef is higher than kefa, chef will take less time… that’s totally wrong logic

**Hint to solve above problem**:–

u have to find time for each but for calculation of time u should avoid division method

**if ur issue resolved accept this answer and close thread otherwise ping me**

**Happy Coding**

1 Like

You have over complicated the solution :

let me try to show you your mistakes in your code…

Here is the problem…

```
if(cc==ck){
if(vc>vk)
printf("Chef\n");
else if(vk>vc)
printf("Kefa\n");
else
printf("Draw\n");
}
}
```

if cc==ck the it doesn’t mean that whose velocity is less will reach first…

#counter example…

#1

#1 11 4 2 4

#here inputs are x1 x2 x3 v1 v2

hence

x1<x3<x2

as per question

#here chef will take

(4-1)/2 = 3/2 = 1.5 secs

#while kefa will take

(11-4)/4 =7/4 = 1.75 secs

#so chef wins…

#but as per your solution kefa wins…

I have seen tons of accepted solutions all have used this logic:

suppose distance between bottle and restaurant is 10 and velocity of guy is 6

then time required will be 10/6.

while i have make use of counter i.e in how many step will guy reach to the bottle from his restuarent .

```
let say dis=10;
vel=6;
counter=0
while(dis greater than 0)
{
dis=dis-vel;
counter++;
}
```

Now based on this counter one can identify who will take more steps to reach to bottle.

```
if(counter1 less than counter2)
person1 reaches earlier then person2
else if (counter2 less than counter1)
person2 reaches earlier then person2
else // both take same steps
{
if (vel1 greater than vel2)
person1 reaches first
else
person2 reaches first
}
```

Now whats wrong in this logic can any one plz tell why im getting WA.Problem is very basic

I have updated my solution link still getting WA. Now can u plz find an logical error or test case for which it fails

my code gives Kefa. btw from problem constraints 1 8 11 4 2 doesn’t satisfy as kefas position should be greater then bottle and chefs position.

1 Like

#### actually it has very simple solution… no loops nothing…

#we should compare their time to get soln…

#time= distance/velocity

so

#let tc be time taken by chef and tk by kefa

hence

#tc is to be compared with tk

#### tc=dc/vc;

#### tk=dk/vk;

but then you may fall in problem with float values

hence let u check the sign of tc-tk

#### let temp = tc-tk…

#### hence temp = (dc/vc)-(dk/vk)…

#but this may lead to wrong answer due to float…

hence lets find

temp2 =temp*vc*vk = (dc*vk) - (dk*vc);

Now you may check that sign of temp is same as sign of temp 2…

hence finding sign of temp2 will also do…

hence the simple solution is

temp=(dc*vk)-(dk*vc);

if(temp>0)

chef

else if (temp<0)

kefa

else

draw

#note : take all data members in long long it to avoid wrong answer due to overflow…

now check my answer @code_man

wait again u made mistake while dividing with velocity.

v1 is chefs velocity

v2 is kefas velocity

Are u in hurry bro:)

there is no step concept in this question… t is not integer… it is a float… chef and kefa keeps running even when t=1.00001 ,1.00002 …

hence comparing velocity when steps are same doesn’t seem correct…

example test case:

1 11 4 2 4

here steps of both will be 2… but when you do calculations on paper then chef wins…

but according to your code kefa wins…

1 Like

okay now ?? answer was correct just forgot to change previous step

HERE is my soln link in case you need reference…

#alternate soln is edit cc==ck part in your code as…

temp=(ck*vc)-(cc*vk);

#temp>0 -> chef

#temp<0 -> kefa

#temp==0 -> draw

#remember taking long long int

you can accept my answer if it was appropriate…

Or do let me know what was inappropriate or what u didn’t liked… just for improving my communication and explaination skills…

PS: I do worry about my accept rate. As well as skills…

answer updated, check it again

@code_man Bro, my above answer is now updated, have a look