Max is a electrician working for private telecommunication company .Max is assigned to a task to provide connection to every home. But he thinks wire provided to him is not sufficient in length so he decide to find the minimum length of wire to connect every house. But max is not able to find it .Max want you to help him find what will be minimum distance.


This question was based on one of the applications of MST .MST gives us the minimum distance to cover all given nodes. To know more about mst click here.

// C++ program for Kruskal's algorithm
// to find Minimum Spanning Tree of a
// given connected, undirected and weighted
// graph
#include <bits/stdc++.h>
using namespace std;
// a structure to represent a 
// weighted edge in graph
class Edge {
	int src, dest, weight;
// a structure to represent a connected, 
// undirected and weighted graph
class Graph {
	// V-> Number of vertices, E-> Number of edges
	int V, E;
	// graph is represented as an array of edges.
	// Since the graph is undirected, the edge
	// from src to dest is also edge from dest
	// to src. Both are counted as 1 edge here.
	Edge* edge;
// Creates a graph with V vertices and E edges
Graph* createGraph(int V, int E)
	Graph* graph = new Graph;
	graph->V = V;
	graph->E = E;
	graph->edge = new Edge[E];
	return graph;
// A structure to represent a subset for union-find
class subset {
	int parent;
	int rank;
// A utility function to find set of an element i
// (uses path compression technique)
int find(subset subsets[], int i)
	// find root and make root as parent of i
	// (path compression)
	if (subsets[i].parent != i)
			= find(subsets, subsets[i].parent);
	return subsets[i].parent;
// A function that does union of two sets of x and y
// (uses union by rank)
void Union(subset subsets[], int x, int y)
	int xroot = find(subsets, x);
	int yroot = find(subsets, y);
	// Attach smaller rank tree under root of high
	// rank tree (Union by Rank)
	if (subsets[xroot].rank < subsets[yroot].rank)
		subsets[xroot].parent = yroot;
	else if (subsets[xroot].rank > subsets[yroot].rank)
		subsets[yroot].parent = xroot;
	// If ranks are same, then make one as root and
	// increment its rank by one
	else {
		subsets[yroot].parent = xroot;
// Compare two edges according to their weights.
// Used in qsort() for sorting an array of edges
int myComp(const void* a, const void* b)
	Edge* a1 = (Edge*)a;
	Edge* b1 = (Edge*)b;
	return a1->weight > b1->weight;
// The main function to construct MST using Kruskal's
// algorithm
void KruskalMST(Graph* graph)
	int V = graph->V;
	Edge result[V]; // Tnis will store the resultant MST
	int e = 0; // An index variable, used for result[]
	int i = 0; // An index variable, used for sorted edges
	// Step 1: Sort all the edges in non-decreasing
	// order of their weight. If we are not allowed to
	// change the given graph, we can create a copy of
	// array of edges
	qsort(graph->edge, graph->E, sizeof(graph->edge[0]),
	// Allocate memory for creating V ssubsets
	subset* subsets = new subset[(V * sizeof(subset))];
	// Create V subsets with single elements
	for (int v = 0; v < V; ++v) 
		subsets[v].parent = v;
		subsets[v].rank = 0;
	// Number of edges to be taken is equal to V-1
	while (e < V - 1 && i < graph->E) 
		// Step 2: Pick the smallest edge. And increment
		// the index for next iteration
		Edge next_edge = graph->edge[i++];
		int x = find(subsets, next_edge.src);
		int y = find(subsets, next_edge.dest);
		// If including this edge does't cause cycle,
		// include it in result and increment the index
		// of result for next edge
		if (x != y) {
			result[e++] = next_edge;
			Union(subsets, x, y);
		// Else discard the next_edge
	// print the contents of result[] to display the
	// built MST
	int minimumCost = 0;
	for (i = 0; i < e; ++i) 
// 		cout << result[i].src << " -- " << result[i].dest
// 			<< " == " << result[i].weight << endl;
		minimumCost = minimumCost + result[i].weight;
	// return;
	cout <<minimumCost<< endl;
// Driver code
int main()
	int V ; // Number of vertices in graph
	int E; // Number of edges in graph
	Graph* graph = createGraph(V, E);
	for(int i=0;i<E;i++){
	int sr,de,len;
	graph->edge[i].src =sr-1;
	graph->edge[i].dest =de-1;
	graph->edge[i].weight =len;
	// Function call
	return 0;