PROBLEM LINK:
Contest Division 1
Contest Division 2
Contest Division 3
Contest Division 4
Setter: Devendra Singh
Tester: Aryan, Satyam
Editorialist: Devendra Singh
DIFFICULTY:
592
PREREQUISITES:
None
PROBLEM:
Devendra just had a million-dollar idea and he needs funds to startup. He was recently invited to Sasta Shark Tank (A TV show where entrepreneurs pitch their ideas to investors hoping to get investment in return).
He was offered deals from two investors. The first investor offers A dollars for 10% of his company and the second investor offers B dollars for 20% of his company. Devendra will accept the offer from the investor whose valuation of the company is more. Determine which offer will Devendra accept or if both the offers are equally good.
For example, if the first investor offers 300 dollars for 10% of the company, then the first investor’s valuation of the company is 3000 dollars since 10% of 3000 = 300. If the second investor offers 500 dollars for 20% of the company, then the second investor’s valuation of the company is 2500 dollars since 20% of 2500 = 500.
EXPLANATION:
The first investor offers A dollars for 10% of the company, then the first investor’s valuation of the company is (100/10)\cdot A= 10\cdot A dollars. The second investor offers B dollars for 20% of the company, then the second investor’s valuation of the company is (100/20)\cdot B= 5\cdot B dollars. We just need to compare these two valuations of the company by the investors and if first investor’s valuation is higher, then he should accept the offer from the first investor else if the second investor’s valuation is higher, he should accept the offer from the second investor else both offers are equally good and he can choose any of them.
TIME COMPLEXITY:
O(1) for each test case.
SOLUTION:
Tester-1's Solution
/* in the name of Anton */
/*
Compete against Yourself.
Author - Aryan (@aryanc403)
Atcoder library - https://atcoder.github.io/ac-library/production/document_en/
*/
#ifdef ARYANC403
#include <header.h>
#else
#pragma GCC optimize ("Ofast")
#pragma GCC target ("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
//#pragma GCC optimize ("-ffloat-store")
#include<bits/stdc++.h>
#define dbg(args...) 42;
#endif
// y_combinator from @neal template https://codeforces.com/contest/1553/submission/123849801
// http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2016/p0200r0.html
template<class Fun> class y_combinator_result {
Fun fun_;
public:
template<class T> explicit y_combinator_result(T &&fun): fun_(std::forward<T>(fun)) {}
template<class ...Args> decltype(auto) operator()(Args &&...args) { return fun_(std::ref(*this), std::forward<Args>(args)...); }
};
template<class Fun> decltype(auto) y_combinator(Fun &&fun) { return y_combinator_result<std::decay_t<Fun>>(std::forward<Fun>(fun)); }
using namespace std;
#define fo(i,n) for(i=0;i<(n);++i)
#define repA(i,j,n) for(i=(j);i<=(n);++i)
#define repD(i,j,n) for(i=(j);i>=(n);--i)
#define all(x) begin(x), end(x)
#define sz(x) ((lli)(x).size())
#define pb push_back
#define mp make_pair
#define X first
#define Y second
#define endl "\n"
typedef long long int lli;
typedef long double mytype;
typedef pair<lli,lli> ii;
typedef vector<ii> vii;
typedef vector<lli> vi;
const auto start_time = std::chrono::high_resolution_clock::now();
void aryanc403()
{
#ifdef ARYANC403
auto end_time = std::chrono::high_resolution_clock::now();
std::chrono::duration<double> diff = end_time-start_time;
cerr<<"Time Taken : "<<diff.count()<<"\n";
#endif
}
long long readInt(long long l, long long r, char endd) {
long long x=0;
int cnt=0;
int fi=-1;
bool is_neg=false;
while(true) {
char g=getchar();
if(g=='-') {
assert(fi==-1);
is_neg=true;
continue;
}
if('0'<=g&&g<='9') {
x*=10;
x+=g-'0';
if(cnt==0) {
fi=g-'0';
}
cnt++;
assert(fi!=0 || cnt==1);
assert(fi!=0 || is_neg==false);
assert(!(cnt>19 || ( cnt==19 && fi>1) ));
} else if(g==endd) {
if(is_neg) {
x=-x;
}
assert(l<=x&&x<=r);
return x;
} else {
assert(false);
}
}
}
string readString(int l, int r, char endd) {
string ret="";
int cnt=0;
while(true) {
char g=getchar();
assert(g!=-1);
if(g==endd) {
break;
}
cnt++;
ret+=g;
}
assert(l<=cnt&&cnt<=r);
return ret;
}
long long readIntSp(long long l, long long r) {
return readInt(l,r,' ');
}
long long readIntLn(long long l, long long r) {
return readInt(l,r,'\n');
}
string readStringLn(int l, int r) {
return readString(l,r,'\n');
}
string readStringSp(int l, int r) {
return readString(l,r,' ');
}
void readEOF(){
assert(getchar()==EOF);
}
vi readVectorInt(int n,lli l,lli r){
vi a(n);
for(int i=0;i<n-1;++i)
a[i]=readIntSp(l,r);
a[n-1]=readIntLn(l,r);
return a;
}
bool isBinaryString(const string s){
for(auto x:s){
if('0'<=x&&x<='1')
continue;
return false;
}
return true;
}
// #include<atcoder/dsu>
// vector<vi> readTree(const int n){
// vector<vi> e(n);
// atcoder::dsu d(n);
// for(lli i=1;i<n;++i){
// const lli u=readIntSp(1,n)-1;
// const lli v=readIntLn(1,n)-1;
// e[u].pb(v);
// e[v].pb(u);
// d.merge(u,v);
// }
// assert(d.size(0)==n);
// return e;
// }
const lli INF = 0xFFFFFFFFFFFFFFFL;
lli seed;
mt19937 rng(seed=chrono::steady_clock::now().time_since_epoch().count());
inline lli rnd(lli l=0,lli r=INF)
{return uniform_int_distribution<lli>(l,r)(rng);}
class CMP
{public:
bool operator()(ii a , ii b) //For min priority_queue .
{ return ! ( a.X < b.X || ( a.X==b.X && a.Y <= b.Y )); }};
void add( map<lli,lli> &m, lli x,lli cnt=1)
{
auto jt=m.find(x);
if(jt==m.end()) m.insert({x,cnt});
else jt->Y+=cnt;
}
void del( map<lli,lli> &m, lli x,lli cnt=1)
{
auto jt=m.find(x);
if(jt->Y<=cnt) m.erase(jt);
else jt->Y-=cnt;
}
bool cmp(const ii &a,const ii &b)
{
return a.X<b.X||(a.X==b.X&&a.Y<b.Y);
}
const lli mod = 1000000007L;
// const lli maxN = 1000000007L;
lli T,n,i,j,k,in,cnt,l,r,u,v,x,y;
lli m;
string s;
vi a;
//priority_queue < ii , vector < ii > , CMP > pq;// min priority_queue .
int main(void) {
ios_base::sync_with_stdio(false);cin.tie(NULL);
// freopen("txt.in", "r", stdin);
// freopen("txt.out", "w", stdout);
// cout<<std::fixed<<std::setprecision(35);
T=readIntLn(1,1e2);
while(T--)
{
const lli A=readIntSp(1e2,1e4);
const lli B=readIntLn(1e2,1e4);
assert(A%100==0&&B%100==0);
if(2*A==B){
cout<<"aNy"<<endl;
continue;
}
if(2*A>B){
cout<<"fIrSt"<<endl;
continue;
}
cout<<"sEcOnD"<<endl;
} aryanc403();
readEOF();
return 0;
}
Tester-2's Solution
#include <bits/stdc++.h>
using namespace std;
#ifndef ONLINE_JUDGE
#define debug(x) cerr<<#x<<" "; _print(x); cerr<<nline;
#else
#define debug(x);
#endif
#define ll long long
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
/*
------------------------Input Checker----------------------------------
*/
long long readInt(long long l,long long r,char endd){
long long x=0;
int cnt=0;
int fi=-1;
bool is_neg=false;
while(true){
char g=getchar();
if(g=='-'){
assert(fi==-1);
is_neg=true;
continue;
}
if('0'<=g && g<='9'){
x*=10;
x+=g-'0';
if(cnt==0){
fi=g-'0';
}
cnt++;
assert(fi!=0 || cnt==1);
assert(fi!=0 || is_neg==false);
assert(!(cnt>19 || ( cnt==19 && fi>1) ));
} else if(g==endd){
if(is_neg){
x= -x;
}
if(!(l <= x && x <= r))
{
cerr << l << ' ' << r << ' ' << x << '\n';
assert(1 == 0);
}
return x;
} else {
assert(false);
}
}
}
string readString(int l,int r,char endd){
string ret="";
int cnt=0;
while(true){
char g=getchar();
assert(g!=-1);
if(g==endd){
break;
}
cnt++;
ret+=g;
}
assert(l<=cnt && cnt<=r);
return ret;
}
long long readIntSp(long long l,long long r){
return readInt(l,r,' ');
}
long long readIntLn(long long l,long long r){
return readInt(l,r,'\n');
}
string readStringLn(int l,int r){
return readString(l,r,'\n');
}
string readStringSp(int l,int r){
return readString(l,r,' ');
}
/*
------------------------Main code starts here----------------------------------
*/
ll MAX=100000;
ll tes_sum=0;
vector<string> YS={"YES","yes","yES","YeS","yEs","YEs","Yes","yeS"};
vector<string> NO={"NO","no","No","nO"};
void solve(){
ll a=readIntSp(100,10000);
ll b=readIntLn(100,10000);
assert((a%100)==0);
assert((b%100)==0);
a=2*a-b;
if(a==0){
cout<<"AnY\n";
}
else if(a>0){
cout<<"fiRsT\n";
}
else{
cout<<"sEcOnD\n";
}
return;
}
int main(){
ios_base::sync_with_stdio(false);
cin.tie(NULL);
#ifndef ONLINE_JUDGE
freopen("input.txt", "r", stdin);
freopen("output.txt", "w", stdout);
freopen("error.txt", "w", stderr);
#endif
ll test_cases=readIntLn(1,100);
while(test_cases--){
solve();
}
assert(getchar()==-1);
return 0;
}
Editorialist's Solution
#include "bits/stdc++.h"
using namespace std;
#define ll long long
#define pb push_back
#define all(_obj) _obj.begin(),_obj.end()
#define F first
#define S second
#define pll pair<ll, ll>
#define vll vector<ll>
const int N=1e5+11,mod=1e9+7;
ll max(ll a,ll b) {return ((a>b)?a:b);}
ll min(ll a,ll b) {return ((a>b)?b:a);}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
void sol(void)
{
int a,b;
cin>>a>>b;
if(2*a>b)
cout<<"FIRST\n";
else if(2*a<b)
cout<<"SECOND\n";
else
cout<<"ANY\n";
return ;
}
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL),cout.tie(NULL);
int test=1;
cin>>test;
while(test--) sol();
}