SUMEVOD help

Hello guys!
I’m trouble with this question.
Contest Page | CodeChef .
Could you please help me to figure out the problem?
import java.util.Scanner;

public class Main {

public  static int evenSum(int n) {
	int sum = 0;
    int i = 1;
	int cursor = i;
	
	
	
	for( i = 1; i <= n ; i++) {
        cursor = i * 2;
		sum = sum+cursor ;

	}
	return sum;
}
public  static int oddSum(int n) {
	int sum = 0;
	int i = 1;
	int cursor = i;

	for(i = 1; i <=n ; i++) {
	 cursor = (i * 2) -1;
	 if( cursor %2 ==1){
	     sum  = sum + cursor;
	 }
	}
	return sum;

}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println();
int n = sc.nextInt();

	System.out.println( oddSum(n) + " " +evenSum(n));
}

}

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This will help:

1 Like

I wrote this code, output is coming it is still not accepting
#include
using namespace std;

int main() {
int n;
cin>>n;
int evenSum = 0;
int evenCurr = 2;
int oddCurr = 1;
int oddSum = 0;
for(int i=1; i<=n; i++){
evenSum += evenCurr;
evenCurr +=2;
}
for(int i=0; i<n; i++){
oddSum += oddCurr;
oddCurr +=2;
}
cout<<oddSum<<" "<<evenSum;
return 0;
}

@anushka5653 change all the Datatypes from int to long(see constraints)…
#include <bits/stdc++.h>
using namespace std;

int main()
{
long n;
cin >> n;
long evenSum = 0;
long evenCurr = 2;
long oddCurr = 1;
long oddSum = 0;
for (long i = 1; i <= n; i++)
{
evenSum += evenCurr;
evenCurr += 2;
}
for (long i = 0; i < n; i++)
{
oddSum += oddCurr;
oddCurr += 2;
}
cout << oddSum << " " << evenSum;
return 0;
}

1 Like

Can’t we do like this???

int main() {
	// your code goes here
	int N, even_sum, odd_sum;
	cin >> N;
	odd_sum=N*N;
	even_sum=odd_sum+N;
	cout << odd_sum << " " << even_sum;
	return 0;
}

Yeah it worked, Thanks : )
I was trying to solve this question but couldn’t solve but now after changing the datatypes, I am able to solve this
Thanks