sumOfDigits is some how wrong. Please help me understand why

help
1

Can someone please explain how my code continues to get a wrong answer? It’s like CodeChefe wants their answer, and doesn’t care if it is correct or not.

class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		Scanner in = new Scanner (System.in);
		int temp, n , sum = 0;
        temp = in.nextInt();
		
		while (temp > 0) {
			
			n = temp % 10;
			sum = sum + n;
			temp /= 10;
		}
		
		
		System.out.println(sum);
	}
}


Input 
87

Output
15
2

You should reread the question. It very clearly states

Input
The first line contains an integer T , total number of testcases. Then follow T lines, each line contains an integer N .

1 Like
3

So I need to implement a for loop with the t value. Do I initialize t, or ask the user to give a value?

4

ask user to give value of t and then write in the format below
int t;
cin>>t;

while(t–){
your code
}

5

Ask the user for t
If t =5 then type 5 number
12
13
45
65
78

6

If you mean this Problem, then don’t ask the user; just read in the number of testcases - the Input section tells you the exact format that the test input takes.

The Example Input gives you some nice test input (and the corresponding expected output): for the input

3 
12345
31203
2123

your program should output precisely the following:

15
9
8

In general, I’d advise making sure that your program gives he right output for the Example Input before you submit - you can use the “Run” and the “Custom Input” features of the Codechef IDE to help you check this :slight_smile:

1 Like
7

So I seem to be getting closer, but the output is the sum of 15 + 9 + 8. Should I’m thinking I need to make testcase an array.

8 
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		Scanner in = new Scanner (System.in);
        int t=in.nextInt();
        while(t-- > 0){
		  int temp, n , sum = 0;
          temp = in.nextInt();
	      while (temp > 0) {
			n = temp % 10;
			sum = sum + n;
			temp /= 10;
		  }
          System.out.println(sum);
        }
	}
}

According to my limited knowledge of java, This should work.

1 Like
9

everule1, thanks for the help and inspiration! I was able to get it to work with the following:

import java.util.Scanner;

public class sumOfDigits {

	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		
		System.out.println("Please enter a test number: ");
		int t = in.nextInt();

		for (int i = 0; i < t; i++) {
			int temp, n, sum = 0;
			System.out.println("please enter a number: ");
			temp = in.nextInt();
			while (temp > 0) {

				n = temp % 10;
				sum = sum + n;
				temp /= 10;

			}
			System.out.println(sum);
		}
		in.close();
		

	}
}

I learned that if you declare the int temp, n, sum = 0; outside of the first loop, then it sums up each number.

Will add 15 + 9 + 8

public class sumOfDigits {

	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		
		System.out.println("Please enter a test number: ");
		int t = in.nextInt();
        int temp, n, sum = 0;

		for (int i = 0; i < t; i++) {
			
			System.out.println("please enter a number: ");
			temp = in.nextInt();
			while (temp > 0) {

				n = temp % 10;
				sum = sum + n;
				temp /= 10;

			}
			System.out.println(sum);
		}
		in.close();
		

	}
}