[Practice](CodeChef: Practical coding for everyone SWITCH_CASE)
Author: Nilprasad Birajdar
Tester: Rushikesh Thakare
Editorialist: Shadab Shaikh
DIFFICULTY:
CAKEWALK
PREREQUISITES:
None
PROBLEM:
Given a number N, if the number is between 1 and 10 both inclusive then return the number in words (Lower case English Alphabets) otherwise return “not in range”.
.
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SOLUTIONS:
Setter's Solution
#include
using namespace std;
int main(){
int t;
cin>>t;
while(t–){
int N;
cin>>N;
switch (N)
{
case 1: cout<<“one”<<endl; break;
case 2: cout<<“Two”<<endl; break;
case 3: cout<<“Three”<<endl;break;
case 4: cout<<“Four”<<endl; break;
case 5: cout<<“Five”<<endl; break;
case 6: cout<<“Six”<<endl; break;
case 7: cout<<“Seven”<<endl;break;
case 8 :cout<<“Eight”<<endl; break;
case 9: cout<<“Nine”<<endl;break;
case 10:cout<<“Ten”<<endl; break;
default :cout <<“not in range”<<endl;break;
}
}
return 0;
}