Time Limit for Golang?

What is the default timelimit for Golang? Is it the same as C, C++ or some relaxation is provided as in Python or Java ?

The reason being I tried to code the solution for problem CNOTE in March Challenge in Golang using O(n) complexity and I got TLE for some cases. The same logic was used for my C solution that easily passes the time limit.

My solution is http://www.codechef.com/viewsolution/6453605

According to the updated official codechef blog, the time limits are as given below.

Java – 2X

Python – 5X

Ruby – 3X

PHP – 3X

Lisp clisp – 3X

Lisp sbcl – 3X

Scala – 2X

C# – 2X

All other languages – 1X

Here X stands for the time limit states in the problem page itself.

So " go language " falls under 1X category

For more details visit this link.

hi @technophyle , if you are still looking for solution this code gets AC on all test cases

package main

import (

var scr = bufio.NewReader(os.Stdin)
var ocr = bufio.NewWriter(os.Stdout)

func readInts() []int {
    arr := make([]int, 0)
    tmp, _ := scr.ReadString('\n')
    tmp = strings.TrimRight(tmp, "\r\n")
    for _, s := range strings.Split(tmp, " ") {
        i, _ := strconv.Atoi(s)
        arr = append(arr, i)
    return arr

func main() {
    var t, x, y, k, n, p, c int
    defer ocr.Flush()

    fmt.Fscanf(scr, "%d\n", &t)
    for i := 1; i <= t; i++ {
        // fmt.Fscanf(scr, "%d %d %d %d\n", &x, &y, &k, &n);
        arr := readInts()
        x, y, k, n = arr[0], arr[1], arr[2], arr[3]
        flag := false

        for j := 1; j <= n; j++ {
            // fmt.Fscanf(scr, "%d %d\n", &p, &c)
            arr = readInts()
            p, c = arr[0], arr[1]
            if x - y <= p && k >= c {
                flag = true   

        if flag {
            fmt.Fprintln(ocr, "LuckyChef")
           // ocr.Flush()
        } else {
            fmt.Fprintln(ocr, "UnluckyChef")