I tried using std::sort and std::vector and i’m still getting the time limit error. Perhaps using vectors isn’t fast enough.
#include <iostream>
#include <algorithm>
#include <vector>
int main(int argc, const char * argv[])
{
std::vector<int> array;
int size = 0;
int temp = 0;
std::cin >> size;
for(int i = 0; i<array.size(); i++){
std::cout << "Enter data: ";
std::cin >> temp;
array.push_back(temp);
}
std::sort(array.begin(), array.end());
for(int j = 0; j<array.size(); j++){
std::cout << array[j] << std::endl;
}
return 0;
}
kuruma
2
Hi,
You need to use faster I/O methods, like, scanf()/printf().
Also, after fixing this you will get WA, because you are NOT respecting I/O format because you are sending to stdout the sentence: "Enter data: ".
This is not correct and you should remove it to get AC…
Besides, there’s a bigger mistake in your code.
You attempt to access the size of the array, by doing array.size(), but, you declared the vector without any size beforehand.
To declare a vector called array which starts with 10 numbers (i.e. array.size()==10) you can do:
vector<int> array(10);
If you do:
vector<int> array;
then, on the second declaration the vector is empty and using array.size() is bit meaningless…
If you want to see my AC solution as reference:
http://www.codechef.com/viewsolution/3253358
Also, use this problem (and some more in practice section) to get to know C++… You won’t regret it
Best,
Bruno