I am getting run time error for my code…please help whats wrong…here is my code on the given link

http://www.codechef.com/viewsolution/4224555

There can be a situation where temp array needs to store more than its capacity, so you can’t define its space to be only 100. Take temp to be dynamic and its space to be equal to capacity of array.

Also include <stdlib.h> into your code. Feel free to ask more!

Simply use sort function in algorithm header.

You are not checking when testcase_count==0.

[t <= 10^6] it can be 0,if it is 0 then the program should end.

i guess your modified code gives run time error when you give t as 0.

Reply if it still gives RTE

Use counting sort since the range of elements is small (0 <= A[i] < = 10^6). Maintain a array **freq[]** of size **10^6** where **count[ele]** stores the frequency of **ele** in the given array. Then print **ele** count[ele] times where **ele** goes from **0 to 10^6** . Hope it helps.

Instead of using any sort, you can follow a very simple approach here as the problem clearly states that numbers are in the range of **1 to 10^6**. So take an array of size **10^6+1** and initialize it to **0**.

Take the **input** as x ,take **max_value** as 0 and do the following

```
x : input
max_value : 0
increment a[x]
keep updating **max_value** here.
```

Now when you are finished taking the input just run a iterative loop from **0 to max_value** and print it. The loop can look like

```
for i:0 to max_value
if a[i]
while(a[i]--)
print i
```

Time complexity : O(n)

Hope it helps!!

I made those changes what you said but its still showing run time error…