TVDISC - Editorial

editorial
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PROBLEM LINK:

Practice
Contest: Division 1
Contest: Division 2
Contest: Division 3
Contest: Division 4

Author: Hriday
Testers: Abhinav Sharma, Venkata Nikhil Medam
Editorialist: Nishank Suresh

DIFFICULTY:

447

PREREQUISITES:

None

PROBLEM:

There are two TVs: the first costs A rupees and has a discount of C rupees, while the second costs B rupees and has a discount of D rupees. Which one is cheaper?

EXPLANATION:

This is a simple application of if-conditions. The overall cost of the first TV is A - C rupees, while that of the second TV is B - D rupees. Compute these two values, then use if-else conditions to compare them and find out which one is less, or if they are equal.

TIME COMPLEXITY:

\mathcal{O}(1) per test case.

CODE:

Tester (C++) 
// Tester: Nikhil_Medam
#include <bits/stdc++.h>
using namespace std;
#define endl "\n"

int t, a, b, c, d;
int32_t main() {
    cin >> t;
    while(t--) {
        cin >> a >> b >> c >> d;
        if(a - c < b - d) {
            cout << "First" << endl;
        }
        else if(a - c > b - d) {
            cout << "Second" << endl;
        }
        else {
            cout << "Any" << endl;
        }
    }
	return 0;
}
Editorialist (Python) 
for _ in range(int(input())):
    a, b, c, d = map(int, input().split())
    if a-c < b-d:
        print('first')
    else:
        print('second' if a-c > b-d else 'any')