What's wrong in the code?

general
1

Code-:Submission #125827023 - Codeforces
Question-:Problem - 352A - Codeforces

2

Anyone?

3

I don’t see any code there. Just a bunch of #define statements. You might want to share your approach as well.

4

It is there…just scroll down :grinning:

5

The Code if there is a problem regarding viewing-:
int main(){
ll m;
cin >> m;
vLL v;
for (int i = 0; i < m; i++)
{
ll ele;
cin >> ele;
v.pb(ele);
}
ll count=0;
for (int i = 0; i < m; i++)
{

            if(v[i]==0)
            count++;
    }
    if(count==0)
    cout<<"-1";
    else{
    sort(v.begin(), v.end(),greater<int>());
    ll sum;
    do
    {
    ll i = 0;
    ll sum = 0;
            do
            {
                    sum += v[i];
                    if (i != v.size() - 1)
                            sum = sum * 10;
                    i++;

            } while (i != v.size());
            if (v.size() == 1)
            {
                    cout << "0";
                    break;
            }
            else{
                    ll j=0;
                    v.erase(v.begin()+j);
                 }
    } while (sum % 90 != 0);
    cout << sum;}
    return 0;

}

6

The approach is also needed. It’s difficult otherwise.

7

AC solution

1 Like
8

Approach is wrong.You just finding the number made by all elements of array,
…
Try this approah:

             check divisibility by 9 and 10. for 9 check if sum of digits is divisible by 9 or not and for 10 check is there any 0 in the array.
number will be divisible by 9 if and only if number of 5's are divisible by 9.
I think It will help
1 Like
9

clude
using namespace std;
int main() {
int x;
float y;
cin>>x>>y;
if(x % 5 == 0 && x<=y -0.5)
y=y-x-0.5;
if(x % 5 !== 0 && x<=y -0.5)
y=y;
else
y=y;
cout<<y;
return 0;
}
what is wrong in this code?