Please tell me where I went wrong in my solution to this problem.It would be a great help for me if you please point out my mistakes.Thanks.

You should not have the line print “Enter the number of test cases” Since it’s an online judge, it takes that line as the output so, only output it wants is either “Elevator” or “Stairs”. And also delete those lines “v is”

Hope this helps!!

your solution

your logic seems perfectly fine, but

Input

3

5 10 15

2 10 14

7 14 10

Your output

Elevator

Expected output

Elevator

Stairs

Stairs

So for some reason, it doesn’t run enough times to solve the other test cases. I’m not familiar with C, so I don’t know what’s wrong!!

You also dont ahve a ‘;’ after while loop.

```
while(T--);
```

is equivalent to

```
while(T--){}//Empty while loop
```

Fix that as well. And as @kunnu120 said, dont print superfluous print statements, its a machine checking your answer.

@vijju123 it took me so long to realize that he had a semi colon after the while loop, look at my profile I ran this program so many times. Then saw the semi colon I was like Ahh, man!! I thought the problem was with the scanf thing so I was searching the problem on google and everywhere. because I don’t know C lmao

Hahahahahahahahah

I have developed some spotting skills . I think I should apply for exam copy correction of my juniors X) *evil*

Second year

wow, you know more than most seniors do, when you started coding?

Roughly 6 month experience

Stay a while here and you will see for yourself *wink*

I’ll try my best bro

why “e = (float)2*n/V2;

s = (float)sqrt(2)*n/V1;” when you already declared e and s as float?

but anyways thank you very much for help.

@psnarsikar “e = (float)2n/V2;”

It’s called typecasting, you right that e and c are already float but n v1 & v2 are integers, so why we typecast?

Because if you do this “e = 2n/v2’” then what computer see is float = int which is not right by typecasting you’re saying (float = (float) int) the computer will see this as float = float that’s why we do typecasting.