WHICHDIV - Editorial

PROBLEM LINK:

Practice
Contest: Division 1
Contest: Division 2
Contest: Division 3

Author: Arjun Arul
Tester: Shubham Anand Jain
Editorialist: Nishank Suresh

DIFFICULTY:

Cakewalk

PREREQUISITES:

None

PROBLEM:

Given the rating R of a person, output which division he belongs to.

EXPLANATION:

Simply do exactly as the problem asks - input R, check which of the 3 ranges it lies in, and print the corresponding division. The simplest implementation of this is to use if-else statements.

TIME COMPLEXITY:

\mathcal{O}(1) per testcase.

SOLUTIONS:

Setter's Solution
#include<bits/stdc++.h>
using namespace std;
#define ll long long int
#define pb push_back
#define rb pop_back
#define ti tuple<int, int, int>
#define pii pair<int, int>
#define pli pair<ll, int>
#define pll pair<ll, ll>
#define mp make_pair
#define mt make_tuple

using namespace std;
  
FILE *fp;
ofstream outfile;

long long readInt(long long l,long long r,char endd){
    long long x=0;
    int cnt=0;
    int fi=-1;
    bool is_neg=false;
    while(true){
        // char g=getchar();
        char g = getc(fp);
        if(g=='-'){
            assert(fi==-1);
            is_neg=true;
            continue;
        }
        if('0'<=g && g<='9'){
            x*=10;
            x+=g-'0';
            if(cnt==0){
                fi=g-'0';
            }
            cnt++;
            assert(fi!=0 || cnt==1);
            assert(fi!=0 || is_neg==false);
            
            assert(!(cnt>19 || ( cnt==19 && fi>1) ));
        } else if(g==endd){
            if(is_neg){
                x= -x;
            }
            // cerr << x << " " << l << " " << r << endl;
            assert(l<=x && x<=r);
            return x;
        } else {
            assert(false);
        }
    }
}
string readString(int l,int r,char endd){
    string ret="";
    int cnt=0;
    while(true){
        // char g=getchar();
        char g=getc(fp);
        assert(g != -1);
        if(g==endd){
            break;
        }
        cnt++;
        ret+=g;
    }
    assert(l<=cnt && cnt<=r);
    return ret;
}
long long readIntSp(long long l,long long r){
    return readInt(l,r,' ');
}
long long readIntLn(long long l,long long r){
    return readInt(l,r,'\n');
}
string readStringLn(int l,int r){
    return readString(l,r,'\n');
}
string readStringSp(int l,int r){
    return readString(l,r,' ');
}

const int maxt = 1000, minr = 1000, maxr = 4500;
const string newln = "\n", space = " ";


int main()
{   
    int t, r; cin >> t;
    while(t--){
        cin >> r;
        int ans = 1;
        if(r < 1600)ans = 3;
        else if(r < 2000)ans = 2;
        cout << ans << endl;
    }
} 
Tester's Solution
//By TheOneYouWant
#include <bits/stdc++.h>
using namespace std;
#define fastio ios_base::sync_with_stdio(0);cin.tie(0)

int main(){
	fastio;

	int tests;
	cin >> tests;

	while(tests--){
		int r;
		cin >> r;
		if(r >= 2000){
			cout << 1 << endl;
		}
		else if(r >= 1600){
			cout << 2 << endl;
		}
		else{
			cout << 3 << endl;
		}
	}

	return 0;
}
Editorialist's Solution
for _ in range(int(input())):
    rating = int(input())
    if rating >= 2000:
        print(1)
    elif rating >= 1600:
        print(2)
    else:
        print(3)