 # Why i am unable to get a full marks in the program from june challenge

question url =https://www.codechef.com/problems/CHFICRM
why am i not getting full marks through the above solution`Preformatted text`

same with this solution of mine.And i can’t figure out what is the fault
https://www.codechef.com/viewsolution/34430723

yes exactly i am unable to figure it out .

hi

i made the same mistake the first time i submitted this
The problem is that you have taken a single array to store all coins
Instead, make three variables for the three different types of coins

1 Like

i code in PYTH 3.6, so really sorry if i made a mistake in understanding your approach

here’s my sol:
check this out

i hope its simple enough to be translated easily to your language
feel free to ask again if you don’t understand my approach

1 Like

also, check out the editorial

1 Like

thank you i understood your approach but still unable to get the answer that y my code was not accepted

https://www.codechef.com/viewsolution/33935485

You can check out my solution in C.
Or can see the editorial.

1 Like

in case of coin of 15 is given :
you should first give 10 if you have
I HAVE MADE SOME CHANGES IN YOUR PROGRAM now it is working
https://www.codechef.com/viewsolution/34446353

1 Like

in my solution…i have commented the wrong approach i had used earlier.
For certain testcases, the code goes wrong
earlier i used chef_money = 0 for the total money chef has and it gave WA

my logic turned out to be wrong
for everytime, i did not subtract the change from the total money chef has

Yep, me too. The question was about to keep the no of coins. but I was keeping the total of change in a single variable.

1 Like

there must be a logical error where you are not adding/subtracting in the right places.

if a[i] = 5
+= 5
if a[i] = 10
+= 10
-= 5
if a[i] = 15
+=15
-=10 or -= (5+5)

i think this part is wrong

you are doing -15 for 15 value coin instead of -10
A person must pay 5 for an icecream, so if coin value > 5, chef returns coin value - 5

did you get it?

1 Like

For the case of coin valued 15, you need to empty up 10’s coin first and then use up 5’s coin.

As per your code logic you are checking which coin is valued more and you are using that, which shouldn’t be the case.
Example case : 5 10 5 5 5 15 10 10

2 Likes

In case of 15 why are you giving him 15 back? @anon92172001

2 Likes

yeah…that gave me WA earlier

yes, he should give coin value - 5, so his logic is wrong

1 Like

And Here is the Code:
#include<bits/stdc++.h>
//#include
using namespace std;

typedef long long ll;
typedef int ii;
typedef vector vi;

#define T while(t–)
#define for1(i,a,b) for(i=a;i<=b;i++)
#define pb push_back
//#define mp make_pair

ii main()
{

``````ii t,n,i; cin>>t;

while(t--)
{

cin>>n; ii numbers={}; vi v;

for1(i,0,n-1)
{

cin>>numbers[i];
v.pb(numbers[i]);

}

multiset<ii> chef;

for1(i,0,n-1)
{

if(v[i]==5) chef.insert(5);
else if(v[i]==10 && chef.count(5)>0)
{

chef.insert(10); chef.erase(chef.find(5));

}
else if(v[i]==15 && chef.count(10)>0)
{

chef.insert(15); chef.erase(chef.find(10));

}
else if(v[i]==15 && chef.count(5)>1)
{

chef.insert(15); chef.erase(chef.find(5)); chef.erase(chef.find(5));
}
else
{
break;
}

}

if(i==n) cout<<"YES"<<"\n";
else cout<<"NO"<<"\n";

v.clear(); chef.clear();

}
``````

}

Yup.

Here is my solution to this problem.
https://www.codechef.com/viewsolution/33663941