my problem link is
And my approach to this problem is whenever two L 's and two T’s and two I’s and two M’s and two E’s are present then i print “YES” otherwise “NO”.
and i think there is no modifications needed to string for getting output…
correct me if my approach is wrong.
I don’t think your approach will give the right answer for the test case LLTTIIMME.
Output must be ‘YES’ because the given string can be re arranged to LTIMEMITL.
Same problem with my code but i have overcome the exception you told but again it showing wrong answer while submitting.
PLS HELP
in your code in 16line your statement print(o) printing unnecessary data will leads to wrong answer
Ohh sorry i forgot to remove it
But after removing it again showing wrong ans 
check here i have removed it–CodeChef: Practical coding for everyone
Your code isn’t exactly checking the occurrence of those alphabets individually. It is only giving the total occurrence so something like TTTTTTTTTTTTTTTTTTTTTTTTT is giving output YES.
I have corrected what you said but again wrong answer 
here check corrected solution it now runs two times per word of “LTIME”—CodeChef: Practical coding for everyone
You just have to make the YES and NO capital. Gave AC after that change.
WTF!!!
because of this capital small thing the whole thing messed up.Now ans is correct.
THANK YOU BRO 