Why is this code running for only 1 time for t=4?

general
,
1

#include<stdio.h>
int main()
{
int t;
scanf("%d",&t);
int i;
for(i=0;i<t;i++)
{
char c[1];
scanf("%c",&c[0]);
if(c[0]==‘B’||c[0]==‘b’)
{
printf(“Battleship\n”);
}
else if(c[0]==‘C’||c[0]==‘c’)
{
printf(“Cruiser\n”);
}
else if(c[0]==‘D’||c[0]==‘d’)
{
printf(“Destroyer\n”);
}
else if(c[0]==‘F’||c[0]==‘f’)
{
printf(“Frigate\n”);
}
}
return 0;
}

2

Which problem are you trying to solve?

2 Likes
3

FLOW010

4

https://www.codechef.com/problems/FLOW010

5

I cant understand your language very well. How about you see my solution in Java, I just solved and maybe you can understand something.
Here: CodeChef: Practical coding for everyone

1 Like
6

It’s BattleShip not Battleship.
newline or enter is also a character . Your c[0] char array contains ‘\n’ . To avoid it you can use fflush or simply update your code

scanf("%d ",&t);
scanf("%c ",&c[0]);

Here is a space before the end of double quote.

2 Likes
7 
char ch;
std::scanf("%d", &t);
std::scanf(" %c", &ch); // ignore the endline after %d, then read a char
1 Like