# PROBLEM LINK

# PROBLEM STATEMENT

The city of Wuhan is afflicted by one of the deadliest viruses ever known to mankind. There are N centres in the city and every centre has A[i] people afflicted with the virus. The government has a total of M masks that needs to be given to the people afflicted by the virus. The government has appointed you to inform them whether these M marks will be enough for the afflicted people or they need to buy more.So print 1 if the M masks will be enough or 0 if they need to buy more.

# SOLUTION

You just need to calculate the sum of the patients in each centre and compare it with the total number of masks that the government has. Print 1 if masks are greater than or equal to the total number of patients , else print 0.# SOLUTION CODE

```
#include <bits/stdc++.h>
#define loop(i,n) for(i=0;i<n;i++)
using namespace std;
typedef long long int ll;
bool prime(ll s)
{
if (s <= 1) return false;
if (s <= 3) return true;
if (s%2 == 0 || s%3 == 0) return false;
for (ll i=5; i*i<=s; i=i+6)
if (s%i == 0 || s%(i+2) == 0)
return false;
return true;
}
int main()
{
ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
int t=1;
cin>>t;
while(t--)
{
ll ans = 0;
ll n,m;
cin>>n>>m;
for(ll i=0;i<n;i++)
{
ll x;
cin>>x;
ans+=x;
}
if(m>=ans)
cout<<1<<"\n";
else
cout<<0<<"\n";
}
return 0;
}
```