# XMAS20 - Editorial

Contest

Setter: aviroop001

Tester: debrc , mishra_roshan

Editorialist: aviroop001

Simple

# PREREQUISITES:

Basic observations, Comparisons

# PROBLEM:

Belsnickel especially loves three children from The Schrute Farms, namely Dwight, Mose and Fannie and he wants to give them cash gifts. The oldest child, Dwight, proposes that a distribution of money is fair only if an older descendant always receives more money than any younger sibling; if two siblings share the same age, they should receive the same amounts of cash reward.

For each valid child, the n^t child is age_n years old and received cash_n cash as reward. Determine whether this distribution of money is in terms with Dwight Schrute.

# EXPLANATION

The basic concept behind the solution is to compare the cash reward each child is getting. We compare a cash prize with the other cash prizes and the respective ages of the children, if it does not fit our criteria, we can simply print NO, else YES.

# SOLUTIONS:

Setter's Solution
C++
``````#include <bits/stdc++.h>
using namespace std;
int main(){
int t, a[3], c[3];
cin >> t;
while (t){
for (int i = 0; i < 3; i++)
cin >> a[i];
for (int i = 0; i < 3; i++)
cin >> c[i];
bool flag = true;
if (a[1] > a[0]){
if (c[1] <= c[0]){
cout << "NO";
flag = false;
}
}
else if (a[1] < a[0]){
if (c[1] >= c[0]){
cout << "NO";
flag = false;
}
}
else{
if (c[1] != c[0]){
cout << "NO";
flag = false;
}
}
if (flag){
if (a[2] > a[1]){
if (c[2] <= c[1]){
cout << "NO";
flag = false;
}
}
else if (a[2] < a[1]){
if (c[2] >= c[1]){
cout << "NO";
flag = false;
}
}
else{
if (c[2] != c[1]){
cout << "NO";
flag = false;
}
}
}
if (flag){
if (a[2] > a[0]){
if (c[2] <= c[0]){
cout << "NO";
flag = false;
}
}
else if (a[2] < a[0]){
if (c[2] >= c[0]){
cout << "NO";
flag = false;
}
}
else{
if (c[2] != c[0]){
cout << "NO";
flag = false;
}
}
}
if (flag)
cout << "YES";
if (t != 1)
cout << endl;
t--;
}
return 0;
}

``````

Feel free to Share your thought process .
Suggestions are welcomed as always had been.