In one week for sure I suppose.
Ah great looks like I ain’t qualifying this time. I am In 12th and got 49 lmao
I’m in 12th and got 142. The extra 42 I got I’m a bit doubtful of it might fail main tests. Good luck to you for the results 
Even I am getting 49 let’s see whether we qualify or not
r u using python or c++ or Java
I use c++,because I only know c++ lol
hopefully, we do. I used python and got TLE on the first problem 
Should have learned cpp earlier- only know a bit.
I think I ran the script after commenting out the freopen part, but idk, that could have been the reason
What would you reckon the cutoff will be for 11th?
Its not always the language though…what implementation did you use? like what was your logic?
yeah, I was also using python I wasn’t able to optimize the first question solution.
I am new to cp so not quite sure what technique I did but I think I just brute forced it. So basically I kept track of the current location and increased it on each iteration if the position i or j is less than that of the ith or jth position of the final destination. If both ith and jth position is possible to take then my code takes the one which has a lesser value(best available position). I ran a lot of test cases it worked but the time limit just exceeded when I submitted it. I couldn’t think of another solution at the moment and just left it as it is. (Problem1- vacation)
I think for 11th, anything >=100 should suffice. That’s what I feel.
Sheeeesh why do you think it’s gonna be so high? Like in 19’ it was 25 for everyone. So I’d expect something around that ig. Ah anyways hope it’s lower.
The reason is, anyone who even had seen even the very basics of 2d prefix sums would have solved problem 1. Also, I will stop my predictions now too lol
Anybody please share the solution/logic of problem-2. Problem-1 was quite simple and i solved it easily.
You just gave me a heart attack.
I have got 64 and I am in class 6. May I know what are the chances of passing?
Thanks
100% chances to qualify if after additional test cases your score remains the same.