# PROBLEM LINK: Cake and Precision

* Author:* Vaibhav Chauhan

*Sumeet Pachauri*

**Tester:***Vaibhav Chauham*

**Editorialist:**# Difficulty:

Easy

# Prerequisites:

Strings,functions

# Explanation:

As we know that in each minute cake gets double of it’s previous size so let’s say cake was fully baked at t seconds so at t-1 seconds it was half baked because at every second it doubles it’s size and baking is directly proportional to size.

For example- let cake is half baked in 4 seconds, so in next one second it will double it’s size and also it is fully baked now in 5 seconds.

As our task is to add 2 seconds to half baked cake so we will print 6 in our example.

# General

Generally we can say that we have to take an integer n , and print n+1.

# Solution:

## Setter's Solution C++

```
#include <bits/stdc++.h>
using namespace std;
string answer_puzzle(string number)
{
int carry = 0;
//First add 1 to the last digit
int digit = number[number.size() - 1] - '0' + 1;
carry = digit/10;
digit = digit % 10;
number[number.size() - 1] = digit + '0';
int i = number.size() - 2;
for(; i >= 0 ; --i )
{
if ( carry == 0 )
break;
digit = number[i] - '0' + digit + carry;
carry = digit/10;
digit = digit % 10;
number[i] = digit + '0';
}
string result;
if ( carry )
{
char carry_char = carry + '0';
result.push_back(carry_char);
}
result += number;
return result;
}
int main()
{
int T;
cin >>T;
while( T-- )
{
string a;
cin >> a;
cout << answer_puzzle(a) << endl;
}
}
```

## Setter's Solution Python

```
t = (int)(input())
for i in range(t):
s = (int)(input())
s = s + 1
print(s)
```

Please give me suggestions if anything is unclear so that I can improve. Thanks